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(C) $I. [(Ph_3P)_2PdCl_2PdCl_2]$: The $Pd$ atom is in $+2$ oxidation state. $EAN = 46 - 2 + (4 	imes 2) = 52 
eq 54$ (Atomic number of $Xe$). Thus,i

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$NF-NF-F-F$

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(C) $I. [(Ph_3P)_2PdCl_2PdCl_2]$: The $Pd$ atom is in $+2$ oxidation state. $EAN = 46 - 2 + (4 	imes 2) = 52 
eq 54$ (Atomic number of $Xe$). Thus,it is $NF$.$II. [NiBrCl(en)]$: The $Ni$ atom is in $+2$ oxidation state. $EAN = 28 - 2 + (4 	imes 2) = 34 
eq 36$ (Atomic number of $Kr$). Thus,it is $NF$.$III. Na_4[Fe(CN)_5NOS]$: The $Fe$ atom is in $+2$ oxidation state. $EAN = 26 - 2 + (5 	imes 2) + 2 = 36 = [Kr]$. Thus,it is $F$.$IV. Cr(CO)_3(NO)_2$: The $Cr$ atom is in $0$ oxidation state. $EAN = 24 - 0 + (3 	imes 2) + (3 	imes 2) = 36 = [Kr]$. Thus,it is $F$.Therefore,the sequence is $NF-NF-F-F$.

Choose the correct option regarding the following complex compounds which follow $(F)$ and do not follow $(NF)$ the Sidgwick $EAN$ rule:
$I. [(Ph_3P)_2PdCl_2PdCl_2]$
$II. [NiBrCl(en)]$
$III. Na_4[Fe(CN)_5NOS]$
$IV. Cr(CO)_3(NO)_2$
$I-II-III-IV$

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Choose the correct option regarding the following complex compounds which follow $(F)$ and do not follow $(NF)$ the Sidgwick $EAN$ rule:$I. [(Ph_3P)_2PdCl_2PdCl_2]$$II. [NiBrCl(en)]$$III. Na_4[Fe(CN)_5NOS]$$IV. Cr(CO)_3(NO)_2$$I-II-III-IV$